Code | Station Name | Arrives | Departs | PF | Halt | Day |
---|---|---|---|---|---|---|
PTN | Patan | Start | 18:25 | -- | 1 | |
RUJ | Ranuj | 18:50 | 18:51 | -- | 1m | 1 |
DHJ | Dhinoj | 19:13 | 19:14 | -- | 1m | 1 |
PHC | Panchot | 19:27 | 19:28 | -- | 1m | 1 |
MSH | Mahesana Junction | 19:50 | End | -- | 1 |
Train | Train Name | S | M | T | W | T | F | S |
---|---|---|---|---|---|---|---|---|
409WR | Patan Ahmedabad Passenger | S | M | T | W | T | F | S |
413WR | Patan Ahmedabad Fast Passenger | S | M | T | W | T | F | S |
Train | Train Name | S | M | T | W | T | F | S |
---|---|---|---|---|---|---|---|---|
59481 | Mahesana Patan Passenger | S | M | T | W | T | F | S |
59483 | Mahesana Patan Passenger | S | M | x | W | T | F | x |
1: What is the train number of Patan Mahesana Passenger?
A: Patan Mahesana Passenger Train Number is 433WR.
2: What is the Schedule of Patan Mahesana Passenger?
A: Patan Mahesana Passenger train runs from Patan to Mahesana Junction. It departs from Patan at 18:25 and reaches Mahesana Junction at 19:50.
3: What is the platform number of Patan Mahesana Passenger or on which platform the train usually arrives?
A: Train 433WR arrives on platform number -- at Patan and at platform number -- at .Mahesana Junction
4: What is the travel route and time of Patan Mahesana Passenger?
A: Patan Mahesana Passenger took 1h 25m to cover total distance of 40 km between Patan and Mahesana Junction. The average speed of Patan Mahesana Passenger is 28 km/hr with a peak speed of NA
5: How many total halts Patan Mahesana Passenger has on its journey?
A: Patan Mahesana Passenger took total 3 halts to cover its journey.
6: From where Patan Mahesana Passenger starts and at which time? Or What is the source station of Patan Mahesana Passenger?
A: Patan Mahesana Passenger starts from Patan at 18:25 at Platform number --.
7: What is the last station of Patan Mahesana Passenger and when the train reaches to its destination?
A: Its reaches Mahesana Junction at 19:50 which is the last station of its journey.